Optimal. Leaf size=130 \[ \frac{1}{9} \sqrt{1-2 x} (5 x+3)^{5/2}-\frac{5}{24} \sqrt{1-2 x} (5 x+3)^{3/2}-\frac{925}{864} \sqrt{1-2 x} \sqrt{5 x+3}+\frac{6553 \sqrt{\frac{5}{2}} \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )}{2592}+\frac{2}{81} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right ) \]
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Rubi [A] time = 0.0518948, antiderivative size = 130, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.269, Rules used = {101, 154, 157, 54, 216, 93, 204} \[ \frac{1}{9} \sqrt{1-2 x} (5 x+3)^{5/2}-\frac{5}{24} \sqrt{1-2 x} (5 x+3)^{3/2}-\frac{925}{864} \sqrt{1-2 x} \sqrt{5 x+3}+\frac{6553 \sqrt{\frac{5}{2}} \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{5 x+3}\right )}{2592}+\frac{2}{81} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right ) \]
Antiderivative was successfully verified.
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Rule 101
Rule 154
Rule 157
Rule 54
Rule 216
Rule 93
Rule 204
Rubi steps
\begin{align*} \int \frac{\sqrt{1-2 x} (3+5 x)^{5/2}}{2+3 x} \, dx &=\frac{1}{9} \sqrt{1-2 x} (3+5 x)^{5/2}-\frac{1}{9} \int \frac{\left (-8-\frac{45 x}{2}\right ) (3+5 x)^{3/2}}{\sqrt{1-2 x} (2+3 x)} \, dx\\ &=-\frac{5}{24} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{1}{9} \sqrt{1-2 x} (3+5 x)^{5/2}+\frac{1}{108} \int \frac{\sqrt{3+5 x} \left (\frac{981}{2}+\frac{2775 x}{4}\right )}{\sqrt{1-2 x} (2+3 x)} \, dx\\ &=-\frac{925}{864} \sqrt{1-2 x} \sqrt{3+5 x}-\frac{5}{24} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{1}{9} \sqrt{1-2 x} (3+5 x)^{5/2}-\frac{1}{648} \int \frac{-\frac{32541}{4}-\frac{98295 x}{8}}{\sqrt{1-2 x} (2+3 x) \sqrt{3+5 x}} \, dx\\ &=-\frac{925}{864} \sqrt{1-2 x} \sqrt{3+5 x}-\frac{5}{24} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{1}{9} \sqrt{1-2 x} (3+5 x)^{5/2}-\frac{7}{81} \int \frac{1}{\sqrt{1-2 x} (2+3 x) \sqrt{3+5 x}} \, dx+\frac{32765 \int \frac{1}{\sqrt{1-2 x} \sqrt{3+5 x}} \, dx}{5184}\\ &=-\frac{925}{864} \sqrt{1-2 x} \sqrt{3+5 x}-\frac{5}{24} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{1}{9} \sqrt{1-2 x} (3+5 x)^{5/2}-\frac{14}{81} \operatorname{Subst}\left (\int \frac{1}{-7-x^2} \, dx,x,\frac{\sqrt{1-2 x}}{\sqrt{3+5 x}}\right )+\frac{\left (6553 \sqrt{5}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{11-2 x^2}} \, dx,x,\sqrt{3+5 x}\right )}{2592}\\ &=-\frac{925}{864} \sqrt{1-2 x} \sqrt{3+5 x}-\frac{5}{24} \sqrt{1-2 x} (3+5 x)^{3/2}+\frac{1}{9} \sqrt{1-2 x} (3+5 x)^{5/2}+\frac{6553 \sqrt{\frac{5}{2}} \sin ^{-1}\left (\sqrt{\frac{2}{11}} \sqrt{3+5 x}\right )}{2592}+\frac{2}{81} \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{3+5 x}}\right )\\ \end{align*}
Mathematica [A] time = 0.0623636, size = 92, normalized size = 0.71 \[ \frac{6 \sqrt{1-2 x} \sqrt{5 x+3} \left (2400 x^2+1980 x-601\right )-6553 \sqrt{10} \sin ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )+128 \sqrt{7} \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right )}{5184} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.007, size = 115, normalized size = 0.9 \begin{align*} -{\frac{1}{10368}\sqrt{1-2\,x}\sqrt{3+5\,x} \left ( -28800\,{x}^{2}\sqrt{-10\,{x}^{2}-x+3}+128\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) -6553\,\sqrt{10}\arcsin \left ({\frac{20\,x}{11}}+1/11 \right ) -23760\,x\sqrt{-10\,{x}^{2}-x+3}+7212\,\sqrt{-10\,{x}^{2}-x+3} \right ){\frac{1}{\sqrt{-10\,{x}^{2}-x+3}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 2.81751, size = 112, normalized size = 0.86 \begin{align*} -\frac{5}{18} \,{\left (-10 \, x^{2} - x + 3\right )}^{\frac{3}{2}} + \frac{145}{72} \, \sqrt{-10 \, x^{2} - x + 3} x + \frac{6553}{10368} \, \sqrt{10} \arcsin \left (\frac{20}{11} \, x + \frac{1}{11}\right ) - \frac{1}{81} \, \sqrt{7} \arcsin \left (\frac{37 \, x}{11 \,{\left | 3 \, x + 2 \right |}} + \frac{20}{11 \,{\left | 3 \, x + 2 \right |}}\right ) + \frac{119}{864} \, \sqrt{-10 \, x^{2} - x + 3} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.71346, size = 366, normalized size = 2.82 \begin{align*} \frac{1}{864} \,{\left (2400 \, x^{2} + 1980 \, x - 601\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1} - \frac{6553}{10368} \, \sqrt{5} \sqrt{2} \arctan \left (\frac{\sqrt{5} \sqrt{2}{\left (20 \, x + 1\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{20 \,{\left (10 \, x^{2} + x - 3\right )}}\right ) + \frac{1}{81} \, \sqrt{7} \arctan \left (\frac{\sqrt{7}{\left (37 \, x + 20\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{14 \,{\left (10 \, x^{2} + x - 3\right )}}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{1 - 2 x} \left (5 x + 3\right )^{\frac{5}{2}}}{3 x + 2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.84641, size = 251, normalized size = 1.93 \begin{align*} -\frac{1}{810} \, \sqrt{70} \sqrt{10}{\left (\pi + 2 \, \arctan \left (-\frac{\sqrt{70} \sqrt{5 \, x + 3}{\left (\frac{{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \,{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}}\right )\right )} + \frac{1}{4320} \,{\left (12 \,{\left (8 \, \sqrt{5}{\left (5 \, x + 3\right )} - 15 \, \sqrt{5}\right )}{\left (5 \, x + 3\right )} - 925 \, \sqrt{5}\right )} \sqrt{5 \, x + 3} \sqrt{-10 \, x + 5} + \frac{6553}{10368} \, \sqrt{10}{\left (\pi + 2 \, \arctan \left (-\frac{\sqrt{5 \, x + 3}{\left (\frac{{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{4 \,{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}}\right )\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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